A 10 kg solid cylinder with a 50.0 cm radius has a moment of inertia of 1/2 MR². If a torque of 2.0 N•m is applied to the object, the angular acceleration is A) 1.0 rad/s². B) 1.6 rad/s². C) 1.8 rad/s². D) 2.1 rad/s². E) 2.3 rad/s².

Question

Quizplus · Accepted Answer

The formula for torque is given by 
τ = Iα
where τ is the torque, I is the moment of inertia and α is the angular acceleration.
Rearranging the formula gives
α = τ / I
Substituting the given values, we get
α = 2.0 N·m / (1/2 * 10 kg * 0.5 m^2)
α = 1.6 rad/s^2
Therefore, the angular acceleration is 1.6 rad/s^2 or choice B.

A 10 Kg Solid Cylinder with a 50