A 30.00 kg box slides up a 12.00 meter long incline at an angle of 30.00 degrees above the horizontal. Friction is negligible. The change in gravitational potential energy is
A) 2110 J.
B) 1467 J.
C) 1080 J.
D) 1764 J.
E) 760.0 J.

Question

Quizplus · Accepted Answer

The change in gravitational potential energy is given by the equation:

ΔPE = mgh

where m is the mass of the box, g is the acceleration due to gravity (9.81 m/s^2), and h is the change in height of the box.

To find the change in height, we need to first find the vertical displacement of the box as it moves up the incline. This can be found using trigonometry:

sin(30) = opp/hyp = h/12.00

h = 6.00 meters

Now we can plug in the values for m, g, and h to find ΔPE:

ΔPE = (30.00 kg)(9.81 m/s^2)(6.00 m)
ΔPE = 1764 J

Therefore, the answer is D) 1764 J.

A 3000 Kg Box Slides Up a 12