A 6.00 kg box is pulled up an 8.00 m long incline (with friction) at an angle of 30.0 degrees by a force of 50.0 N parallel to the incline. The coefficient of kinetic friction is 0.100. The work done against friction is
A) 22.0 J.
B) 26.5 J.
C) 30.3 J.
D) 35.2 J.
E) 40.7 J.

Question

Quizplus · Accepted Answer

The work done against friction is calculated using the formula: Work = friction force * distance. The friction force is the product of the normal force and the coefficient of kinetic friction. The normal force is the component of the gravitational force perpendicular to the incline, which is mg*cos(θ). Therefore, the friction force is 0.100 * 6.00 kg * 9.8 m/s² * cos(30°). The work done against friction is this friction force multiplied by the distance (8.00 m), which results in approximately 40.7 J.

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