An 80.0 kg person is riding in an elevator that is accelerating at 2.40 m/s² downward. The apparent weight of the 80.0 kg person measured on a scale in the elevator is A) 592 N. B) 639 N. C) 784 N. D) 855 N. E) 976 N.

Question

Quizplus · Accepted Answer

The apparent weight can be calculated using the formula $w = m(g - a)$, where $m = 80.0 \, \text{kg}$, $g = 9.8 \, \text{m/s}^2$ (acceleration due to gravity), and $a = 2.4 \, \text{m/s}^2$ (acceleration of the elevator). Thus, $w = 80.0 \, \text{kg} \times (9.8 \, \text{m/s}^2 - 2.4 \, \text{m/s}^2) = 80.0 \, \text{kg} \times 7.4 \, \text{m/s}^2 = 592 \, \text{N}$.

An 800 Kg Person Is Riding in an Elevator That Is