On the way to lower floors, an elevator begins its descent from rest with a constant acceleration, descending the first 5.0 m in 1.85 s. What is the apparent weight of a 75 kg man inside the accelerator during this time interval?
A) 0.74 kN
B) 0.52 kN
C) 0.11 kN
D) 1.0 kN

Question

Quizplus · Accepted Answer

The apparent weight is the normal force, which is the actual weight minus the force due to acceleration. Using the equation $ s = ut + \frac{1}{2}at^2 $, we find acceleration $ a $. Then, apparent weight = $ mg - ma $.

On the Way to Lower Floors, an Elevator Begins Its