A projectile is projected from the origin with a velocity of 25.0 m/s at an angle of 50.0 degrees above the horizontal. What is the time of maximum height of the projectile?
A) 1.95 s
B) 2.03 s
C) 2.67 s
D) 3.01 s
E) 3.45 s

Question

Quizplus · Accepted Answer

The time to reach maximum height can be calculated using the formula $t = \frac{v \sin(\theta)}{g}$, where $v$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $9.8 \, \text{m/s}^2$). Plugging in the given values: $t = \frac{25 \sin(50^\circ)}{9.8}$ gives approximately 1.95 seconds.

A Projectile Is Projected from the Origin with a Velocity