A car traveling at 4.0 m/s has a constant acceleration of 2.0 m/s² in the same direction as the velocity. After 3.0 seconds, the distance traveled is A) 21 m. B) 17 m. C) 10 m. D) 13 m. E) 9 m.

Question

Quizplus · Accepted Answer

The distance traveled by the car can be calculated using the formula for distance under constant acceleration: $d = v_0t + \frac{1}{2}at^2$, where $v_0$ is the initial velocity, $a$ is the acceleration, and $t$ is the time. Substituting the given values: $d = 4.0 \, \text{m/s} \times 3.0 \, \text{s} + \frac{1}{2} \times 2.0 \, \text{m/s}^2 \times (3.0 \, \text{s})^2 = 12 \, \text{m} + 9 \, \text{m} = 21 \, \text{m}$.

A Car Traveling at 4