The figure shows the graph of v_xversus time for an object moving along the x-axis. Solve graphically for the average acceleration between t = 5.0 s and t = 9.0 s. A) 4.0 m/s² B) 5.0 m/s² C) 0.5 m/s² D) 0.4 m/s²

Question

Quizplus · Accepted Answer

To find the average acceleration between t = 5.0 s and t = 9.0 s, we need to find the slope of the velocity-time graph during that interval. We can draw a line connecting the points on the graph at t = 5.0 s and t = 9.0 s, and find the slope of that line.

Using a ruler or straight edge, we can draw a line connecting the points (5.0 s, 10 m/s) and (9.0 s, 30 m/s). The change in velocity during that interval is Δv = 30 m/s - 10 m/s = 20 m/s. The time interval is Δt = 9.0 s - 5.0 s = 4.0 s. Therefore, the average acceleration is:

a = Δv/Δt = (20 m/s) / (4.0 s) = 5.0 m/s².

The best choice is therefore B.

The Figure Shows the Graph of Vx versus Time for an Object

The Figure Shows the Graph of V_xversus Time for an Object