A sprinter runs 100.0 m in 9.87 seconds. If he travels at constant acceleration for the first 75.0 m and then at constant velocity for the final 25.0 m, what was his acceleration during the first 75.0 m? A) 1.58 m/s² B) 2.05 m/s² C) 2.10 m/s² D) 2.74 m/s²

Question

Quizplus · Accepted Answer

We can start by using the equation:

d = vt + 1/2at^2

where d is the distance, v is the initial velocity, t is the time, and a is the acceleration.

For the first 75.0 m, we have:

75.0 m = 1/2a(9.87 s)^2

Solving for a, we get:

a = 2(75.0 m)/(9.87 s)^2

a = 2.10 m/s^2

Therefore, the answer is (C), 2.10 m/s^2.

A Sprinter Runs 100