After beta-minus decay of iodine, which has an atomic number of 131 and an atomic mass of 53, the resultant nuclide will have the following mass number (A) and atomic number (Z) :
A) (A) = 131, (Z) = 52
B) (A) = 131, (Z) = 54
C) (A) = 130, (Z) = 53
D) (A) = 132, (Z) = 53
Correct Answer:
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