Assume that customer arrivals at a small cafe can be modeled by a Poisson distribution. The average arrival rate is 3 customers per hour. What is the probability of exactly 1 arrival in the next hour (to two decimal places)?
A) 1.00
B) 0.15
C) 0.30
D) 0.45

Question

Quizplus · Accepted Answer

The probability of exactly k arrivals in a Poisson distribution is given by P(X=k) = (λ^k * e^(-λ)) / k!, where λ is the average rate (3 in this case) and k is the number of arrivals (1 in this case). So, P(X=1) = (3^1 * e^(-3)) / 1! = 3 * e^(-3) ≈ 0.15.

Assume That Customer Arrivals at a Small Cafe Can Be