After Allowing the Reaction to Proceed, You Find That the The Final

After allowing the reaction to proceed, you find that the the final concentrations of each $\frac{[\mathrm{C}][\mathrm{D}]}{[\mathrm{A}][\mathrm{B}]}$ once equilibrium is achieved is $\frac{[0.35][0.35]}{[0.65][0.65]}$
Will the reaction proceed in a forward manner, namely with production of increased concentrations of products?

A) yes, because K_eq is greater than 1
B) no, because K_eq is greater than 1
C) yes, because K_eq is less than 1
D) no, because K_eq is less than 1