Aluminum reacts with oxygen according to the following reaction: 4Al(s)+ 3O₂(g)→ 2Al₂O₃(s)If 24 moles of aluminum are combined with 12 moles of oxygen, how many moles of Al₂O₃ should form?

Question

Quizplus · Accepted Answer

The balanced chemical equation is 4Al + 3O2 → 2Al2O3. With 24 moles of Al, the reaction would ideally consume 18 moles of O2 to produce 12 moles of Al2O3. However, only 12 moles of O2 are available, making O2 the limiting reactant. Thus, 12 moles of O2 would produce 8 moles of Al2O3 according to the stoichiometry of the reaction (3O2:2Al2O3).

Aluminum Reacts with Oxygen According to the Following Reaction: 4Al(s)