What is the heat change when a 53.5 g sample of water [C_water = 4.184 J/(g°C)] is cooled from 98.0°C to 23.2°C?

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Quizplus · Accepted Answer

The heat change (q) can be calculated using the formula q = mcΔT, where m = mass of water, c = specific heat capacity of water, and ΔT = change in temperature. Plugging in the values: q = 53.5 g * 4.184 J/(g°C) * (23.2°C - 98.0°C) = -1.67 x 10^4 J. The negative sign indicates heat is released (cooling).

What Is the Heat Change When a 53