The q value for the following reaction is 178.0 kJ for every mole of CaCO₃ that reacts: CaCO₃(s)→ CaO(s)+ CO₂(g)How much heat would be required to decompose 4.00 mol CaCO₃(s), and is the reaction endothermic or exothermic?

Question

Quizplus · Accepted Answer

To calculate the heat required for the decomposition of 4 mol of CaCO₃, we need to use the given q value (heat per mol) and multiply it by the number of moles of CaCO₃ that react: Heat required = q value x number of moles Heat required = 178.0 kJ/mol x 4.00 mol Heat required = 712 kJ Since heat is required for the reaction to occur, it is endothermic. Therefore, the correct answer is B.

The Q Value for the Following Reaction Is 178