When potassium metal is exposed to air, it forms a coating of potassium oxide, according to the following equation: 4K(s)+ O₂(g)→ 2K₂O(s)If a piece of potassium gains 0.354 g, assuming this gain can be attributed to the above reaction with oxygen, what mass of K₂O formed? Report your answer with the correct number of significant figures and correct units.

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The Answer of When potassium metal is exposed to air, it forms a coating of potassium oxide, according to the following equation: 4K(s)+ O₂(g)→ 2K₂O(s)If a piece of potassium gains 0.354 g, assuming this gain can be attributed to the above reaction with oxygen, what mass of K₂O formed? Report your answer with the correct number of significant figures and correct units.

When Potassium Metal Is Exposed to Air, It Forms a Coating