If 50.0 mL of 0.235 M NaCl solution is diluted to 200.0 mL, what is the concentration of the diluted solution?

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Quizplus · Accepted Answer

The concentration of the diluted solution can be found using the dilution formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Substituting the given values: $0.235 \, \text{M} \times 50.0 \, \text{mL} = C_2 \times 200.0 \, \text{mL}$. Solving for $C_2$ gives $C_2 = 0.0588 \, \text{M}$.

If 500 ML of 0