The proprietor of a rock shop insists that a nugget is pure gold. If the nugget occupies a volume of 5.40 mL, what would its mass have to be if it were truly pure gold? (d_gold = 19.3 g/mL)

Question

Quizplus · Accepted Answer

To find the mass of the nugget if it were pure gold, use the formula for density ($d = \frac{m}{V}$), where $d$ is the density, $m$ is the mass, and $V$ is the volume. Given that the density of gold is 19.3 g/mL and the volume of the nugget is 5.40 mL, the mass ($m$) can be calculated as $m = d \times V = 19.3 \, \text{g/mL} \times 5.40 \, \text{mL} = 104.22 \, \text{g}$. Rounding to the nearest whole number gives 104 g.

The Proprietor of a Rock Shop Insists That a Nugget