TABLE 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture. She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650. The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Table 9-6, suppose the engineer had decided that the alternative hypothesis to test was that the mean was less than 650. Then if the test is performed with a level of significance of 0.05, the null hypothesis would be rejected.

Question

Quizplus · Accepted Answer

To reject the null hypothesis at a level of significance of 0.05, the p-value must be less than or equal to 0.05. However, the given p-value of 0.080 is greater than 0.05, so the null hypothesis would not be rejected.

TABLE 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested