TABLE 11-6
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3 varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in bushels per acre. Treating this as a randomized block design, the results are presented in the table that follows.
-Referring to Table 11-6, the null hypothesis for the randomized block F test for the difference in the means is
A) H₀: μFᵢₑld₁ = μFᵢₑld₂ = μFᵢₑld₃ = μFᵢₑld₄ = μFᵢₑld₅.
B) H₀: μSmᵢth = μWₐlsh = μTᵣₑᵥₒᵣ.
C) H₀: MFᵢₑld₁ = MFᵢₑld₂ = MFᵢₑld₃ = MFᵢₑld₄ = MFᵢₑld₅.
D) H₀: MSmᵢth = MWₐlsh = MTᵣₑᵥₒᵣ.

Question

TABLE 11-6
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3 varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in bushels per acre. Treating this as a randomized block design, the results are presented in the table that follows. 
-Referring to Table 11-6, the null hypothesis for the randomized block F test for the difference in the means is
A) H₀: μFᵢₑld₁ = μFᵢₑld₂ = μFᵢₑld₃ = μFᵢₑld₄ = μFᵢₑld₅. 
B) H₀: μSmᵢth = μWₐlsh = μTᵣₑᵥₒᵣ. 
C) H₀: MFᵢₑld₁ = MFᵢₑld₂ = MFᵢₑld₃ = MFᵢₑld₄ = MFᵢₑld₅. 
D) H₀: MSmᵢth = MWₐlsh = MTᵣₑᵥₒᵣ.

Quizplus · Accepted Answer

The Answer of TABLE 11-6
An agronomist wants to compare the crop yield of 3 varieties of chickpea seeds. She plants all 3 varieties of the seeds on each of 5 different patches of fields. She then measures the crop yield in bushels per acre. Treating this as a randomized block design, the results are presented in the table that follows. 
-Referring to Table 11-6, the null hypothesis for the randomized block F test for the difference in the means is
A) H₀: μFᵢₑld₁ = μFᵢₑld₂ = μFᵢₑld₃ = μFᵢₑld₄ = μFᵢₑld₅. 
B) H₀: μSmᵢth = μWₐlsh = μTᵣₑᵥₒᵣ. 
C) H₀: MFᵢₑld₁ = MFᵢₑld₂ = MFᵢₑld₃ = MFᵢₑld₄ = MFᵢₑld₅. 
D) H₀: MSmᵢth = MWₐlsh = MTᵣₑᵥₒᵣ.

TABLE 11-6 An Agronomist Wants to Compare the Crop Yield of 3