In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of the allele a is 0.3. What is the percentage of the population that is homozygous for this allele?
A) 0.09
B) 0.49
C) 0.9
D) 9.0
E) 49.0

Question

Quizplus · Accepted Answer

The frequency of allele a is 0.3, so the frequency of homozygous aa individuals is (0.3)^2 = 0.09, which is 9.0% of the population.

In a Hardy-Weinberg Population with Two Alleles, a and A