The amount of energy released by the neutron induced fission of ${ } ^ { 235 } \mathrm { U }$ to give ${ } ^ { 141 } \mathrm { Ba }$ , ${ } ^ { 92 } \mathrm { Kr }$ , and three neutrons is _____ 10¹⁰ kJ/mol. (Given, the experimentally determined mass of ${ } ^ { 235 } \mathrm { U }$ = 235.043930 amu, ${ } ^ { 141 } \mathrm { Ba }$ = 140.914411 amu, ${ } ^ { 92 } \mathrm { Kr }$ = 91.926156 amu, and mass of neutron = 1.008665 amu)

Question

Quizplus · Accepted Answer

The energy released in a nuclear reaction is calculated using the mass defect and Einstein's equation $E=mc^2$. The mass defect is the difference between the mass of the reactants and the products. Here, the mass defect is calculated as: $235.043930 - (140.914411 + 91.926156 + 3 \times 1.008665)$. This mass defect is then converted to energy using $E=mc^2$, where $c$ is the speed of light. The energy is approximately -1.67 x 10^10 kJ/mol.

The Amount of Energy Released by the Neutron Induced Fission 235U{ } ^ { 235 } \mathrm { U }235U

The Amount of Energy Released by the Neutron Induced Fission ${ } ^ { 235 } \mathrm { U }$