If the $E ^ { \circ }$ of the galvanic cell is 1.24 V and the $E ^ { \circ }$ of the cathode is 0.57, what is the $E ^ { \circ }$ of the anode?

Question

Quizplus · Accepted Answer

The standard cell potential ($E^\circ_{cell}$) is calculated as $E^\circ_{cathode} - E^\circ_{anode}$. Rearranging to find $E^\circ_{anode}$, we get $E^\circ_{anode} = E^\circ_{cathode} - E^\circ_{cell} = 0.57 V - 1.24 V = -0.67 V$.

If The E∘E ^ { \circ }E∘ Of the Galvanic Cell Is 1

If The $E ^ { \circ }$ Of the Galvanic Cell Is 1