A compound hydrolyzes in water with a rate constant of $1.9 \times 10 ^ { - 3 } \mathrm {~min} ^ { - 1 }$ at pH 6.0 and $26 ^{?}\mathrm { C }$ . The half-life for this reaction is _____ min.

Question

Quizplus · Accepted Answer

The half-life ($t_{1/2}$) for a first-order reaction is given by $t_{1/2} = \frac{0.693}{k}$, where $k$ is the rate constant. Substituting $k = 1.9 \times 10^{-3} \mathrm{min}^{-1}$, we get $t_{1/2} = \frac{0.693}{1.9 \times 10^{-3}} \approx 364.74 \mathrm{min}$, which is closest to $3.6 \times 10^2$ min.

A Compound Hydrolyzes in Water with a Rate Constant Of 1.9