One mole of a gas at 25˚C at a pressure of 2 atms has a volume of 17.8 L. What will the volume of the gas be at a temperature of 35˚C?

Question

Quizplus · Accepted Answer

We can use the combined gas law to solve for the new volume:
(P1*V1)/T1 = (P2*V2)/T2
Plugging in the given values:
(2 atm * 17.8 L) / (298 K) = (P2 * V2) / (308 K)
Solving for V2:
V2 = (2 atm * 17.8 L * 308 K) / (298 K * P2)
Since we are not given a new pressure, we can assume it remains constant (or you could use Gay-Lussac's law and the ideal gas law to find the new pressure). Therefore, P2 = 2 atm:
V2 = (2 atm * 17.8 L * 308 K) / (298 K * 2 atm)
V2 = 18.4 L

One Mole of a Gas at 25˚C at a Pressure