In the gas phase, silver chloride (AgCl) has a dipole moment of 6.080 D. If the percent ionic character in silver chloride is 55.50 %, the Ag-Cl distance is _____ pm.

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Quizplus · Accepted Answer

The percent ionic character is given by the formula: $$ \text{Percent ionic character} = \left( \frac{\text{measured dipole moment}}{\text{calculated dipole moment for 100% ionic bond}} \right) \times 100\% $$Given that the percent ionic character is 55.50% and the dipole moment is 6.080 D, we can rearrange the formula to solve for the Ag-Cl distance, which is related to the calculated dipole moment for a 100% ionic bond. The calculated dipole moment ($\mu$) can be found using the equation $\mu = Q \times r$, where $Q$ is the charge (for a monovalent ion like Ag or Cl, $Q = 1.602 \times 10^{-19}$ C) and $r$ is the distance between the ions. Using the given information and the fact that 1 D = $3.336 \times 10^{-30}$ C·m, we can solve for $r$, which gives us a distance close to 230.1 pm.

In the Gas Phase, Silver Chloride (AgCl) Has a Dipole