What is the de Broglie wavelength of a 20,000.0 pound jet fighter traveling at 1200.0 km/hr?

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Quizplus · Accepted Answer

The de Broglie wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{m}^2 \, \text{kg} / \text{s}$), $m$ is the mass in kilograms, and $v$ is the velocity in meters per second. First, convert the mass of the jet from pounds to kilograms (1 pound = 0.453592 kg) and the velocity from km/hr to m/s (1 km/hr = 0.277778 m/s). The mass of the jet is $20,000.0 \, \text{pounds} \times 0.453592 = 9071.84 \, \text{kg}$, and its velocity is $1200.0 \, \text{km/hr} \times 0.277778 = 333.333 \, \text{m/s}$. Substituting these values into the de Broglie equation gives a wavelength of approximately $2.191 \times 10^{-40} \, \text{m}$, which matches option B.

What Is the De Broglie Wavelength of a 20,000 ×10−10 m\times 10 ^ { - 10 } \mathrm {~m}×10−10 m

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