A 2.0-kg block slides on a frictionless 25° inclined plane. A force of 4.6 N acting parallel to the incline and up the incline is applied to the block. What is the acceleration of the block? A) 1.8 m/s² up the incline B) 2.3 m/s² up the incline C) 6.6 m/s² down the incline D) 1.8 m/s² down the incline E) 2.3 m/s² down the incline

Question

Quizplus · Accepted Answer

First, we need to find the component of the force parallel to the incline. This would be Fpar = Fsin(25°) = 4.6 sin(25°) = 1.98 N.
Next, we can use Newton's second law in the direction parallel to the incline:
Fpar = ma
1.98 N = 2.0 kg * a
a = 0.99 m/s^2.
Since the force is up the incline and the acceleration is down the incline, the answer is 1.8 m/s^2 down the incline (which is the negative of 0.99 m/s^2).

A 20-Kg Block Slides on a Frictionless 25° Inclined Plane