A 1.5-kg object has a velocity of 5 m/s at t = 0. It is accelerated at a constant rate for five seconds after which it has a velocity of (6
+ 12
) m/s. What is the direction of the resultant force acting on the object during this time interval?
A) 65°
B) 56°
C) 61°
D) 49°
E) 27°
Correct Answer:
Verified
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