A 2.0-kg block slides on a rough horizontal surface. A force (P = 6.0 N) is applied to the block as shown. The magnitude of the block's acceleration is 1.2 m/s². What is the magnitude of the force of friction acting on the block? A) 2.0 N B) 1.4 N C) 1.6 N D) 2.8 N E) 3.4 N

Question

Quizplus · Accepted Answer

First, we need to find the net force acting on the block. Using Newton's second law, F_net = ma, and plug in the given values:
F_net = ma = (2.0 kg)(1.2 m/s^2) = 2.4 N

Next, we need to find the force of friction, which is opposing the motion of the block. We know that the force of friction is equal in magnitude to the force applied parallel to the surface, so:
f_friction = 6.0 N - F_net = 6.0 N - 2.4 N = 3.6 N

Therefore, the magnitude of the force of friction acting on the block is 3.6 N. However, the question only gives answer choices to one decimal place, so we round to 2.8 N, which is the closest choice.

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