A 3.0-kg block slides on a rough horizontal surface. A force of 8.0 N acting parallel to the surface is applied to the block. The coefficient of kinetic friction between the block and the surface is 0.15. What is the magnitude of the block's acceleration? A) 1.9 m/s² B) 1.2 m/s² C) 2.3 m/s² D) 1.5 m/s² E) 2.9 m/s²

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Quizplus · Accepted Answer

The net force is the applied force minus the frictional force. Frictional force = coefficient of kinetic friction * normal force = 0.15 * 3.0 kg * 9.8 m/s² = 4.41 N. Net force = 8.0 N - 4.41 N = 3.59 N. Acceleration = net force / mass = 3.59 N / 3.0 kg = 1.2 m/s².

A 30-Kg Block Slides on a Rough Horizontal Surface