In a location where the train tracks run parallel to a road, a high speed train traveling at 60 m/s passes a car traveling at 30 m/s. How long does it take for the train to be 180 m ahead of the car?
A) 2.0 s
B) 3.0 s
C) 6.0 s
D) 9.0 s
E) 18.0 s

Question

Quizplus · Accepted Answer

The relative velocity between the train and the car is 60 m/s - 30 m/s = 30 m/s. 
To cover a distance of 180 m at this relative velocity, the time required is:
time = distance/relative velocity = 180 m/30 m/s = 6.0 s. 
Therefore, the train will be 180 m ahead of the car in 6.0 s.

In a Location Where the Train Tracks Run Parallel to a Road