An object is placed 15 cm in front of a diverging lens whose focal length is 12 cm. Where will the image be located (in cm)?
A) −6.7
B) −7.2
C) −0.15
D) −60
E) −5.0

Question

Quizplus · Accepted Answer

The lens formula is 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. For a diverging lens, the focal length (f) is negative. Given f = -12 cm and u = 15 cm, we solve for v: 1/v = 1/(-12) - 1/15 = -1/20, so v = -20/1 = -20 cm. However, none of the options match this calculation, suggesting a mistake in my initial calculation. Let's correct it: 1/v = 1/(-12) - 1/15 = (-5 - 4)/60 = -9/60 = -3/20, so v = -20/3 = -6.7 cm.

An Object Is Placed 15 Cm in Front of a Diverging