A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RC circuit with R = 10.0 Ω and C = 300 μF. The impedance is
A) 4.68 Ω.
B) 8.84 Ω.
C) 10.0 Ω.
D) 13.4 Ω.
E) 18.8 Ω.

Question

Quizplus · Accepted Answer

The impedance of a series RC circuit can be calculated as follows:

Z = √(R^2 + Xc^2)

where Xc is the capacitive reactance given by:

Xc = 1/(2πfC)

Plugging in the values, we get:

Xc = 1/(2π(60)(300×10^-6)) = 88.4 Ω

Z = √(10^2 + 88.4^2) = 13.4 Ω

Therefore, the impedance of the circuit is 13.4 Ω.

A 600-Hz Ac Generator with a Peak Voltage of 110 V