A bullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. If it enters with a speed of 450 m/s and emerges with a speed of 220 m/s, what is the bullet's acceleration as it passes through the board? A) −500 km/s² B) −550 km/s² C) −360 km/s² D) −520 km/s² E) −275 km/s²

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Quizplus · Accepted Answer

The acceleration can be found using the kinematic equation: $ v^2 = u^2 + 2as $. Solving for $ a $, we get $ a = \frac{v^2 - u^2}{2s} $. Substituting $ v = 220 \, \text{m/s} $, $ u = 450 \, \text{m/s} $, and $ s = 0.14 \, \text{m} $, the acceleration $ a $ is approximately $-550,000 \, \text{m/s}^2$ or $-550 \, \text{km/s}^2$.

A Bullet Is Fired Through a Board, 14