A 4.0-Ω resistor has a current of 3.0 A in it for 5.0 min. How many electrons pass through the resistor during this time interval? A) 7.5 × 10²¹ B) 5.6 × 10²¹ C) 6.6 × 10²¹ D) 8.4 × 10²¹ E) 2.1 × 10²¹

Question

Quizplus · Accepted Answer

The number of electrons passing through the resistor can be calculated using the formula:
Q = It
where Q is the charge passing through the resistor, I is the current in amperes, and t is the time in seconds.

Firstly, we need to convert the time from minutes to seconds: 
t = 5.0 min × 60 s/min = 300 s

Next, we can calculate the charge passing through the resistor: 
Q = (3.0 A) × (300 s) = 900 C

Finally, we can calculate the number of electrons using the formula: 
number of electrons = Q/e
where e is the elementary charge, which is 1.602 × 10^-19 C

number of electrons = (900 C) / (1.602 × 10^-19 C/e) = 5.6 × 10^21

Therefore, the answer is B - 5.6 × 10^21 electrons pass through the resistor during this time interval.

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