A particle (charge = 50 μC) moves in a region where the only force on it is an electric force. As the particle moves 25 cm from point A to point B, its kinetic energy increases by 1.5 mJ. Determine the electric potential difference, V_B − V_A. A) −50 V B) −40 V C) −30 V D) −60 V E) +15 V

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The Answer of A particle (charge = 50 μC) moves in a region where the only force on it is an electric force. As the particle moves 25 cm from point A to point B, its kinetic energy increases by 1.5 mJ. Determine the electric potential difference, V_B − V_A. A) −50 V B) −40 V C) −30 V D) −60 V E) +15 V

A Particle (Charge = 50 μC) Moves in a Region