A charge of 40 pC is distributed on an isolated spherical conductor that has a 4.0-cm radius. Point A is 1.0 cm from the center of the conductor and point B is 5.0 cm from the center of the conductor. Determine the electric potential difference V_A − V_B. A) +1.8 V B) +29 V C) +27 V D) +7.2 V E) +9.0 V

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Quizplus · Accepted Answer

The electric potential difference between two points outside a charged spherical conductor is given by:$$V_A - V_B = k\left(\frac{Q}{r_A} - \frac{Q}{r_B}ight)$$where k is Coulomb's constant, Q is the charge on the conductor, and r_A and r_B are the distances from the points A and B to the center of the conductor, respectively.Substituting the given values into the equation, we get:$$V_A - V_B = (9 	imes 10^9 	ext{ N}\cdot	ext{m}^2/	ext{C}^2)\left(\frac{40 	imes 10^{-12} 	ext{ C}}{0.01 	ext{ m}} - \frac{40 	imes 10^{-12} 	ext{ C}}{0.05 	ext{ m}}ight)$$$$V_A - V_B = +1.8 	ext{ V}$$Therefore, the correct answer is A.

A Charge of 40 PC Is Distributed on an Isolated