Two charges of 15 pC and −40 pC are inside a cube with sides that are of 0.40-m length. Determine the net electric flux through the surface of the cube. A) +2.8 N ⋅ m²/C B) −1.1 N ⋅ m²/C C) +1.1 N ⋅ m²/C D) −2.8 N ⋅ m²/C E) −0.47 N ⋅ m²/C

Question

Quizplus · Accepted Answer

The net electric flux through a closed surface is given by Gauss's law, which states that the net flux is equal to the charge enclosed divided by the permittivity of free space (ε₀). The total charge enclosed is 15 pC - 40 pC = -25 pC. Converting to Coulombs, -25 pC = -25 x 10⁻¹² C. Using Gauss's law, Φ = Q/ε₀ = (-25 x 10⁻¹² C)/(8.85 x 10⁻¹² C²/N·m²) = -2.8 N·m²/C.

Two Charges of 15 PC and −40 PC Are Inside