A charge of 0.80 nC is placed at the center of a cube that measures 4.0 m along each edge. What is the electric flux through one face of the cube? A) 90 N ⋅ m²/C B) 15 N ⋅ m²/C C) 45 N ⋅ m²/C D) 23 N ⋅ m²/C E) 64 N ⋅ m²/C

Question

Quizplus · Accepted Answer

The electric flux through one face of the cube can be calculated using Gauss's law, which states that the electric flux through a closed surface is equal to the charge enclosed by the surface divided by the permittivity of free space ($\epsilon_0$). Since the charge is symmetrically placed at the center of the cube, the flux will be evenly distributed through all six faces. The total flux ($\Phi$) is given by $\Phi = \frac{q}{\epsilon_0}$, where $q = 0.80 \times 10^{-9} C$ and $\epsilon_0 = 8.85 \times 10^{-12} C^2/N \cdot m^2$. Thus, the flux through one face is $\frac{\Phi}{6}$. Calculating gives a value close to 15 N·m^2/C, making option B correct.

A Charge of 0