A 5-kg piece of lead (specific heat 0.03 cal/g⋅°C) having a temperature of 80°C is added to 500 g of water having a temperature of 20°C. What is the final equilibrium temperature (in °C) of the system?
A) 79
B) 26
C) 54
D) 34
E) 20

Question

Quizplus · Accepted Answer

The heat lost by the lead equals the heat gained by the water. Using the formula $m \cdot c \cdot \Delta T$, we set up the equation: $5000 \cdot 0.03 \cdot (80 - T) = 500 \cdot 1 \cdot (T - 20)$. Solving for T gives the final temperature as 34°C.

A 5-Kg Piece of Lead (Specific Heat 0