Determine the work done by 5 moles of an ideal gas that is kept at 100°C in an expansion from 1 liter to 5 liters. A) 2.5 × 10⁴ J B) 1.1 × 10⁴ J C) 6.7 × 10³ J D) 2.9 × 10³ J E) 8.4 × 10³ J

Question

Quizplus · Accepted Answer

The work done by an ideal gas in an isothermal expansion is given by W = -nRTln(V2/V1), where n is the number of moles, R is the gas constant, T is the temperature in Kelvin, and V1 and V2 are the initial and final volumes, respectively. Plugging in the given values, we get W = -5 mol * 8.314 J/mol*K * 373 K * ln(5 L/1 L) = -2.5 * 10^4 J.

Determine the Work Done by 5 Moles of an Ideal