Calculate the pressure amplitude (in N/m²) of a 500 Hz sound wave in helium if the displacement amplitude is equal to 5.0 × 10−⁸ m. (ρ = 0.179 kg/m³, v = 972 m/s.) A) 3.5 × 10−² B) 1.6 × 10−² C) 2.7 × 10−² D) 4.2 × 10−² E) 2.0 × 10−²

Question

Quizplus · Accepted Answer

The pressure amplitude (Pa) of a sound wave can be calculated using the formula:
Pa = ρvωA
where ρ is the density of the medium, v is the speed of sound in the medium, ω is the angular frequency (2πf), and A is the displacement amplitude.

In this case, we are given:
f = 500 Hz
A = 5.0 × 10−18 m
ρ = 0.179 kg/m³
v = 972 m/s

Therefore, ω = 2πf = 2π × 500 = 3141.59 rad/s

Plugging these values into the formula, we have:
Pa = 0.179 × 972 × 3141.59 × 5.0 × 10−18
Pa ≈ 2.7 × 10−12 N/m²

Since the question asks for the pressure amplitude in N/m*U1P1*S1U1P1*U1P1, we need to convert N/m² to N/mS1U1P1S1S1P0:
Pa = 2.7 × 10−12 N/m² = 2.7 × 10−12 N/mS1U1P1S1S1P0 = 2.7 × 10−12 × 10^12 N/mS1U1P1S1S1P0
Pa ≈ 2.7 × 10−S1U1P12S1S1P0 N/mS1U1P1S1S1P0

Therefore, the answer is C) 2.7 × 10−S1U1P12S1S1P0.

Calculate the Pressure Amplitude (In N/m2) of a 500 Hz

Calculate the Pressure Amplitude (In N/m²) of a 500 Hz