Water is sent from a firehose at 30.0 m/s at an angle of 30.0° above the horizontal. What is the maximum height reached by the water?
A) 7.50 m
B) 11.5 m
C) 15.0 m
D) 19.0 m
E) 30.0 m

Question

Quizplus · Accepted Answer

The vertical component of the velocity is $ v_{0y} = 30.0 \, \text{m/s} \times \sin(30.0^\circ) = 15.0 \, \text{m/s} $. Using the formula for maximum height $ h = \frac{v_{0y}^2}{2g} $, where $ g = 9.8 \, \text{m/s}^2 $, we get $ h = \frac{(15.0)^2}{2 \times 9.8} = 11.5 \, \text{m} $.

Water Is Sent from a Firehose at 30