A 20-m long steel wire (cross-section 1.0 cm², Young's modulus 2.0 × 10¹¹ N/m²), is subjected to a load of 25 000 N. How much will the wire stretch under the load? A) 0.25 cm B) 2.5 cm C) 12.5 cm D) 25 cm E) 1.25 cm

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Quizplus · Accepted Answer

The stretch ($\Delta L$) can be calculated using the formula $\Delta L = \frac{FL}{AE}$, where $F$ is the force applied, $L$ is the original length, $A$ is the cross-sectional area, and $E$ is Young's modulus. Substituting the given values: $\Delta L = \frac{25,000 \times 20}{1 \times 2 \times 10^{11}} = 2.5$ cm.

A 20-M Long Steel Wire (Cross-Section 1