A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by (1/3)ML². If a force (F = 5.0 N, θ = 40°) acts as shown, what is the resulting angular acceleration about the pivot point? A) 16 rad/s² B) 12 rad/s² C) 14 rad/s² D) 10 rad/s² E) 33 rad/s²

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The Answer of A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by (1/3)ML². If a force (F = 5.0 N, θ = 40°) acts as shown, what is the resulting angular acceleration about the pivot point? A) 16 rad/s² B) 12 rad/s² C) 14 rad/s² D) 10 rad/s² E) 33 rad/s²

A Uniform Rod of Mass M = 1