Impulse-momentum: A 0.500-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wall and rebounds with 70.0% of its initial kinetic energy. What is the magnitude of the change in momentum of the stone?

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Quizplus · Accepted Answer

Explanation:The change in momentum of the ball is:$$p_f-p_i=mv_f-mv_i$$$$=(0.500	ext{ kg})(20.0	ext{ m/s})-(0.500	ext{ kg})(-14.0	ext{ m/s})$$$$=18.4	ext{ kg}\cdot	ext{m/s}$$The change in momentum of the stone is equal in magnitude but opposite in direction to the change in momentum of the ball, so the magnitude of the change in momentum of the stone is also 18.4 kg∙m/s.

Impulse-Momentum: a 0