Work done by variable forces: A force on a particle depends on position such that F(x) = (3.00 N/
)
+ ( 6.00 N/m) x for a particle constrained to move along the x-axis. What work is done by this force on a particle that moves from x = 0.00 m to x = 2.00 m?
A) 10.0 J
B) 20.0 J
C) - 48.0 J
D) 24.0 J
E) 48.0 J
Correct Answer:
Verified
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