Work-energy theorem: A 7.0-kg rock is subject to a variable force given by the equation
F(x) = 6.0 N - (2.0 N/m)x + (6.0 N/m²)x²
If the rock initially is at rest at the origin, find its speed when it has moved 9.0 m.

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The Answer of Work-energy theorem: A 7.0-kg rock is subject to a variable force given by the equation F(x) = 6.0 N - (2.0 N/m)x + (6.0 N/m²)x² If the rock initially is at rest at the origin, find its speed when it has moved 9.0 m.

Work-Energy Theorem: a 7