Energy conservation with conservative forces: A projectile is fired from ground level at an angle of 40.0° above horizontal at a speed of 30.0 m/s. What is the speed of the projectile when it has reached a height equal to 50.0% of its maximum height?

Question

Quizplus · Accepted Answer

The maximum height can be found using the vertical component of the initial velocity and the formula $ h_{max} = \frac{v_{0y}^2}{2g} $. At 50% of this height, energy conservation (kinetic + potential) allows us to solve for the speed, resulting in approximately 26.7 m/s.

Energy Conservation with Conservative Forces: a Projectile Is Fired from Ground